there is a triangle whose angles are 45, 75, 60. if the side opp. to 75 angle is 9cm then find the value of side opp. to 60 degree????? pls explain!!

here we can use sine rule , according to this rule 

=> ratio of side & sine of oppsite angle is constant..

a/sinA = b/sinB = c/sinC = K

side opposite to 75^o is 9 so ratio = 9/sin75^o

let opposite  side to 60^o is x then ratio = x/sin60^o

ratio is constant so x/sin60 = 9/sin75

  x = (9sin60/sin75)

sin75 = (root3+1)/2(root2) , sin60 = root3/2

 so , x = 9root6/(root3+1)     ans

Approved